(x^2+5)(2x-3)=0

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Solution for (x^2+5)(2x-3)=0 equation: 


Simplifying
(x2 + 5)(2x + -3) = 0

Reorder the terms:
(5 + x2)(2x + -3) = 0

Reorder the terms:
(5 + x2)(-3 + 2x) = 0

Multiply (5 + x2) * (-3 + 2x)
(5(-3 + 2x) + x2(-3 + 2x)) = 0
((-3 * 5 + 2x * 5) + x2(-3 + 2x)) = 0
((-15 + 10x) + x2(-3 + 2x)) = 0
(-15 + 10x + (-3 * x2 + 2x * x2)) = 0
(-15 + 10x + (-3x2 + 2x3)) = 0
(-15 + 10x + -3x2 + 2x3) = 0

Solving
-15 + 10x + -3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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